Timeline for What's the formula giving the % of succesfully maliciously messing the blockchain?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Jul 5, 2014 at 18:35 | answer | added | Buge | timeline score: 2 | |
| Jan 14, 2014 at 0:42 | history | tweeted | twitter.com/#!/StackBitcoin/status/422891352939323392 | ||
| Jan 13, 2014 at 12:41 | history | edited | bitcoinNeverSleeps | CC BY-SA 3.0 |
added 419 characters in body
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| Jan 13, 2014 at 12:20 | comment | added | bitcoinNeverSleeps | @GregHewgill: I think technically it's "50% + 1 miner", not "51%" : ) But, yup, that's basically my question: I had the same intuition as jtorba and people told me it was all wrong: I'd like to understand how it works. | |
| Jan 13, 2014 at 7:46 | comment | added | Greg Hewgill | @jtorba: Your math doesn't make sense. By that logic, a 51% miner has a .51^6 = 0.0176 chance. | |
| Jan 13, 2014 at 7:22 | comment | added | John T | Whoever said 50% chance at 40% hash power is wrong, each block makes it exponentially harder. The chance to mine 6 blocks consecutively with 40% is - .4^6, or ~0.004% chance. | |
| Jan 13, 2014 at 2:58 | review | First posts | |||
| Jan 13, 2014 at 5:58 | |||||
| Jan 13, 2014 at 2:48 | history | edited | bitcoinNeverSleeps | CC BY-SA 3.0 |
edited title
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| Jan 13, 2014 at 2:42 | history | asked | bitcoinNeverSleeps | CC BY-SA 3.0 |