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Jori
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6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 15% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper (last pages).

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 15% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper.

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 15% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper (last pages).

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Jori
  • 1.6k
  • 10
  • 15

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 30%15% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper.

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 30% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper.

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 15% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper.

Source Link
Jori
  • 1.6k
  • 10
  • 15

6 blocks, not 6 clients. The chances of catching up to the block with the transactions that is buried 6 blocks deep is slim. Granted of course that the dishonest party has not a very significant part (say less than 30% or so) of the hashing power. These changes can be calculated using Poisson distribution, as done in Satoshi's original paper.