I want to create a bitcoin address which starts with a certain passphrase (
1mathias, case insensitive). That idea came from this question, and I quite liked it. After some trouble making the file on my Mac, it finally worked.
mbpssd2:vanitygen-master mathias$ ./vanitygen -i -t 4 1Mathias WARNING: Built with OpenSSL 0.9.8y 5 Feb 2013 WARNING: Use OpenSSL 1.0.0d+ for best performance Difficulty: 26838491360 [235.42 Kkey/s][total 2888131518][Prob 10.2%][50% in 18.5h]
It is running for quite some time now, and I want to stop it, and continue with finding an address tomorrow. For what I understand, is 1 in that number addresses that fit my passphrase. So if I would choose '1' as passphrase, there would be 1. The percentage showing in terminal is the current generated (and rejected) addresses, compared to the total amount. So reaching 100% doesn't have anything related to finding an address. I can happen at 0.01%, or at 70% or at 8012%, if you are really unlucky (right?)
From the creator of vanitygen I found the following:
If I stop vanitygen when it reports 60% complete, how do I have it restart where it left off?
You don't need to. The percentage displayed just shows how probable it is that a match would be found in the session so far. If it finds your address with 5% on the display, you are extremely lucky. If it finds your address with 92% on the display, you are unlucky. If you stop vanitygen with 90% on the display, restart it, and it finds your address with 2% on the display, your first session was unlucky, but your second session was lucky
But that does not make sense. If I reach 100%, I am not completely sure that an address has popped up, fitting my passphrase. Is this correct? If I let the program run, and generate a billion addresses, not stopping when (or if) it hit my passphrase, it is even likely that it finds a correct one in the first thousand, as in the last thousand?
I'm quite sure I am right, but I might be missing something. I tried to bold the two areas where I am not sure of.