Suppose below is target difficulty:


So result value must lower than target to select block.

So, If Miner 'A' found:


Will miner 'A' can satisfy target difficulty or not?

And if not then please tell me the reason.


1 Answer 1


Yes. The test is that in order to be a valid proof of work, the hash found must be numerically less than or equal to the target. That is certainly true of the hash found by Miner A in your example.

  • Thanks, Still I am not clear. I referred blockexplorer.com some completed blocks,and found "Hash Value" has same number of Previous zeros as target has. I mean if Target has 4 previous zero(0x000043AbC..),then found hash has same number of zero(0x000024C...). Why all the Found hash same number of zeros? It may also generate more than 4 zeros and satisfy less than target.
    – Tushar
    Aug 14, 2014 at 8:28
  • @tushar: It certainly could have 4 more zeros, but this will only happen 1/65536 of the time, so it's not surprising we rarely see it. Aug 14, 2014 at 15:35

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