3

Moneropedia defines "ring signatures" as:

Ring signatures make sure individual transaction outputs on the blockchain can’t be traced. A ring signature is a group of cryptographic signatures with at least one real participant, but there is no way to tell which in the group is the real one as they all appear valid, while the key image prevents double spends. When sending a transaction, you select some random transaction outputs on the blockchain and mix those with your own “real coins”. Mixing of coins is enforced across the network, making all coins “equal”. Because every transaction output has plausible deniability on their state (spent or unspent), there are no fungibility issues with monero

To read how Monero gives you a privacy by default (unlinkability), see stealth addresses.

A group of cryptographic signatures with at least one real participant, but no way to tell which in the group is the real one as they all appear valid.

It sounds like Moreo's ring signatures are basically a way of building mixing right in. So, is Monero effectively the same as Bitcoin+mixers?

1 Answer 1

4

No. Monero's ring signatures draw on Monero's complete TXO set to create a larger anonymity set.

Monero's method has the disadvantage that since it is unclear which TXO were actually spent, they can never be marked as spent and therefore spent TXO hardly ever leave the TXO set.

In Bitcoin mixers, you're actually dependent on other users also using the same mixer.

2
  • hey @Murch , could you pls elaborate on why that is a disadvantage? Blockchain bloat?
    – kumarz
    Commented Dec 8, 2016 at 15:29
  • 1
    @kumarz: In Bitcoin the UTXO set has been about doubling each year for the past three years. This is with UTXO leaving the UTXO set when they are spent. In Monero, I'd expect this growth to be more pronounced for the TXO set (at similar levels of transactions), because transaction inputs don't shrink the TXO set. Other than the blockchain, the TXO set needs to be kept completely on each node to check whether inputs are valid.
    – Murch
    Commented Dec 8, 2016 at 15:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.