I try to understand how the mining hardware environment is different between Bitcoin when centralized mining ecosystem is more encouraged compare to Zcash or Ethereum where pooling is more encouraged.

So is it true that when you have 2 separate rigs mining bitcoins, each individually not joining a pool, they could compete with each other, as oppose to mining Zcash or Ethereum, the 2 rigs join forces to mine together in the same pool? regards

  • Why do you think Bitcoin mining doesn't use a pool? Almost invariably, they do.
    – Hannah Vernon
    Commented Nov 30, 2017 at 13:25
  • true, but I'm comparing a case when one doesn't join one, that means the rigs are competing with each other even with the same owner, correct?
    – ethereal1m
    Commented Nov 30, 2017 at 14:07

1 Answer 1


There is no difference between bitcoin and zcash here, mining with multiple machines work the same way.

If you have 2 machines they can mine in the same mining pool or separate pools. You choose.

Your machines are never competing against each other. You are the one that get paid for the work of both machines.

If you are solo mining instead of using a pool, the machines are still not competing against each other. They are both trying to find a block for you, the owner.

The bad thing you want to avoid is having both machines do the exact same work. That would be a waste. The second machine wouldn't be doing anything useful. Handing out duplicate work would be a serious fault in the mining pool software.

  • is it possible for the machines to do duplicate work in solo mining? if it yes, what is the case?
    – ethereal1m
    Commented Dec 2, 2017 at 16:57
  • When you solo mine you run local pool software. If you run broken software it could in theory happen. So use good software.
    – Dr.Haribo
    Commented Dec 3, 2017 at 20:01

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.