# Why Bitcoin address are 25-34 bytes long when RIPEMD 160 & SHA-256 are only 20 bytes and 32 bytes long respectively?

(I'm new to Bitcoin & it's technology so correct me wherever u can) .Recently I was reading about Bitcoin and it's underlying technologies. I came to know that for generating addresses Bitcoin uses RIPEMD-160(SHA-256). But most of the Bitcoin Addresses are 25 to 34 Bytes(characters) long & starts with 1 or 3. How is this possible? Is there any underlying Encryption algorithm is there along with Hashing functions like RIPEMD & SHA?

Bitcoin address is generated as follows :

First 256 bits of Private key(k) is generated using underlying operating system's pseudo random number generating function (in wallet).

Then Public key (K) = G * k. , where G is constant on the elliptic curve. i.e. equivalent to k times addition of G and the resulting point K is on the curve which is 65 Bytes.

The address is calculated by performing SHA256 followed by RIPEMD160 on public key (K). so that would be of 160 bits = 20 Bytes of address.

Now, Add version prefix 00(in hex). Perform SHA256 twice on it. Take first 4 Bytes of result and append it to (prefix || address).

Resultant would be final address.

Here you can find a step-by-step description of how bitcoin address is generated: https://en.bitcoin.it/wiki/Technical_background_of_version_1_Bitcoin_addresses

Short answer: Bitcoin address consists of <version_byte><20 bytes of RIPEMD-160(SHA-256(PublicKey))><4 bytes checksum> = 25 bytes in total

Checksum is just first 4 bytes of SHA(SHA()) of previous data