4

Let's assume, the hash 00000000000000000024c0bdbec66a889778c00bc69be0a96cbbd98b75c3ce09 of block #499644 is smaller than 0000000000000000002d429f39afec70c938e888c3417d690bbc85e83529991c of block #499645.

They both have 18 Zeros, then 2=2, but then 4<d.

Which is the smallest hash that has ever been hashed during cryptomining? How many zeros? Which block?

2

The 12 lowest block hashes in Bitcoin, at the time of writing (Dec 16 2017):

| improve this answer | |
  • I'd be interested to know how you generated this list, and why you decided to post the lowest 12. – Adam Millerchip Dec 17 '17 at 4:09
  • 2
    I run bitcoin.sipa.be and the website data is generated from a text file with a list of all blocks with hash and height. I sorted the file based on hash and posted the top 12, to give an idea of how common the top number of zeroes is. – Pieter Wuille Dec 17 '17 at 5:59
3

I don't think there is a site that will show you this information, but it is fairly trivial to find out.

Here's an old Bitcointalk thread that discusses this: https://bitcointalk.org/index.php?topic=29675.0

Here's a python script that will calculate it for you. You will need a bitcoind for it to connect to:

from bitcoinrpc.authproxy import AuthServiceProxy, JSONRPCException
import binascii
import struct

def uint256_to_str(u):
    rs = b""
    for i in range(8):
        rs += struct.pack("<I", u & 0xFFFFFFFF)
        u >>= 32
    return binascii.hexlify(rs)

def uint256_from_str(s):
    s = binascii.unhexlify(s)
    r = 0
    t = struct.unpack("<IIIIIIII", s[:32])
    for i in range(8):
        r += t[i] << (i * 32)
    return r

def byteswap(a):
    return "".join(reversed([a[i:i+2] for i in range(0, len(a), 2)]))

# rpc_user and rpc_password are set in the bitcoin.conf file
rpc_user = "user"
rpc_password = "password"
rpc_connection = AuthServiceProxy("http://%s:%s@127.0.0.1:8332"%(rpc_user, rpc_password))

best_hash = uint256_from_str("ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff")
best_height = 0
counter = 0

while True:
    try:
        commands = [ [ "getblockhash", height] for height in range(counter, counter + 10000) ]
        block_hashes = rpc_connection.batch_(commands)

        for block_hash in block_hashes:
            block_uint256 =  uint256_from_str(byteswap(block_hash))
            if block_uint256 < best_hash:
                best_hash = block_uint256
                best_height = counter
            counter += 1

        print("Processed " + str(counter) + " blocks")
    except Exception as e:
        print(e)
        break;

print("Lowest Block Hash: " + byteswap(uint256_to_str(best_hash).decode()) + " at block height " + str(best_height))

This script gave me the following output:

Lowest Block Hash: 00000000000000000000011246f099d94f91628d71c9d75ad2f9a06e2beb7e92 at block height 458091
| improve this answer | |
2

I improved on this to print the lowest 50 block hashes as well as their heights and the dates they were generated:

from bitcoinrpc.authproxy import AuthServiceProxy, JSONRPCException
import datetime

# rpc_user and rpc_password are set in the bitcoin.conf file
rpc_user = "user"
rpc_password = "password"
rpc_connection = AuthServiceProxy("http://%s:%s@127.0.0.1:8332" %
                                  (rpc_user, rpc_password))

block_cnt = rpc_connection.getblockcount()
block_hashes = []

for n in range(0, block_cnt, 1000):
    commands = [["getblockhash", h] for h in range(n, min(n+1000, block_cnt))]
    block_hashes += rpc_connection.batch_(commands)

block_hashes.sort()

commands = [["getblock", block_hash] for block_hash in block_hashes[0:50]]
blocks = rpc_connection.batch_(commands)

for block in blocks:
    time = datetime.datetime.fromtimestamp(block['time']).strftime('%Y-%m-%d')
    print(block['hash'], block['height'], time)

A new record was just set yesterday!

0000000000000000000000bb5b432a764ad6c7acf677dcd99161abfdf68e698e 500174 2017-12-19
| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.