How do I double SHA-256 the header of block #59,500?

Question

I'm not sure how to combine all of this information. https://blockchain.info/block/00000000096af43105123c499521e1d131d172e7e1bf2ed0843290a921f1f6a7

Version 1

Time Bits 470771548 (is this the right number to use for Time Bits?)

Merkle Root ff682ef66cd1b56213fd4db9462fb138f6d8c16d706d41969a7eacc819528038

Nonce 16641419

Hash of Current Block 00000000096af43105123c499521e1d131d172e7e1bf2ed0843290a921f1f6a7

Hash of Previous Block 00000000023bbab0e78a22d27fbd2d0cd13f8302fb3f560138e0e81d087ac7a1

Answer 1

take first 160 symbols from https://blockchain.info/block/00000000096af43105123c499521e1d131d172e7e1bf2ed0843290a921f1f6a7?format=hex

should I explain more? :))))

update:

01000000 version

a1c77a081de8e03801563ffb02833fd10c2dbd7fd2228ae7b0ba3b0200000000 prev hash

38805219c8ac7e9a96416d706dc1d8f638b12f46b94dfd1362b5d16cf62e68ff merkle hash

27b80a4c timestamp

5c670f1c bits

8bedfd00 nonce

Answer 2

As noted above, you should take the first 80 bytes from the serialized block. Since this data is hex-encoded, and each byte takes two hex-digit to encode, a block header is 80 * 2 = 160 digits.
You will notice that a few fields are inverted, it's because they are represented in little-endian format. Once you double-sha256 this data, you'll find a hash with trailing zeros and not leading, this is also because endianness.

Here is how the mentioned block looks like:
Take the first 160-digits serialized header
01000000a1c77a081de8e03801563ffb02833fd10c2dbd7fd2228ae7b0ba3b020000000038805219c8ac7e9a96416d706dc1d8f638b12f46b94dfd1362b5d16cf62e68ff27b80a4c5c670f1c8bedfd00
And parse:
Version: 01000000 (This is 1 in little-endian)
Previous block hash: a1c77a081de8e03801563ffb02833fd10c2dbd7fd2228ae7b0ba3b0200000000 (Notice the trailing zeroes)
Merkle Root: 38805219c8ac7e9a96416d706dc1d8f638b12f46b94dfd1362b5d16cf62e68ff
Timestamp: 27b80a4c
Bits: 5c670f1c
Nonce: 8bedfd00

A python 3 code that hashes it:

import hashlib
data = bytes.fromhex("01000000a1c77a081de8e03801563ffb02833fd10c2dbd7fd2228ae7b0ba3b020000000038805219c8ac7e9a96416d706dc1d8f638b12f46b94dfd1362b5d16cf62e68ff27b80a4c5c670f1c8bedfd00")
h1 = hashlib.sha256(data).digest()
h2 = hashlib.sha256(h1).digest()
print(h2.hex())

It results in a7f6f121a9903284d02ebfe1e772d131d1e12195493c120531f46a0900000000, that's precisely the little-endian version of 00000000096af43105123c499521e1d131d172e7e1bf2ed0843290a921f1f6a7