# Mining with CPU on difficulty 1 [closed]

I have been playing around cloning Peercoin client. I have found the genesis block for main net, but now I'm trying to mine the block 1 with difficulty set on 1. I connected 4 machines all doing about 5Mh/s. Is it even plausible to find the block? Block retarget is on each block so I guess if I manage to find one difficulty will lower and I will be able to mine easier.

Thanks for any hints.

## closed as off-topic by Pieter Wuille, chytrik, Andrew Chow♦Aug 17 at 3:54

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First of all, I would double check that the difficulty target is really 1, if you're recalculating on every block, how does it handle the first block?

Update: The initial difficulty for peercoin is actually 256, but the calculations below can be tweaked to see it results in 55.5 hours at 5MH/s.

## Time to solve a block

Here is a resource that might help: Generation Calculator. The calculation is:

1. Get the current target. Target for difficulty 1 (Bitcoin) is:

00000000ffffffffffffffffffffffffffffffffffffffffffffffffffffffff

2. Divide by 115792089237316195423570985008687907853269984665640564039457584007913129639935, which is the maximum value of a 256-bit number. You now have the probability of a single hash solving a block.

currentTarget / max256 = 2.33E-10

3. Take the reciprocal of the probability to get the average number of hashes to solve a block.

1/2.33E10 = 4.3E9

4. Divide the average number of hashes by your hash/s (not khash/s) to get the average number of seconds required to solve a block.

4.3E9 / 5E6 = 860 seconds or 14.3 minutes

• Thank you. Difficulty 1 is the difficulty the peercoin daemon is showing me, on testnet it was showing 0.14 and I was managing to find blocks fine in probably 5 minutes each. How can I double check the difficulty target more than just watching getinfo from network? And thank you for the answer. – Bloodir Wiredancer Nov 9 '18 at 20:33
• The source code is where I'd check first, but I'm assuming the initial difficulty is the same for peercoin, this was more of a generic answer. – JBaczuk Nov 9 '18 at 20:40
• static CBigNum bnProofOfWorkLimit(~uint256(0) >> 32); static CBigNum bnInitialHashTarget(~uint256(0) >> 40); – Bloodir Wiredancer Nov 9 '18 at 20:43
• The initial target is not a difficulty of 1, in that case, it is 256, which changes the calcs above to currentTarget / max256 = 9E-13, 1 / 9E-13 = 1E12, and 1(1E12 / 5E6) / 3600 = 55.5 hours. – JBaczuk Nov 9 '18 at 21:12
• Ah ok. Thats a bit too long, but thanks a lot for your explanation. One more thing. Can you explain me how did you get the diff 256 from the above code? Thanks – Bloodir Wiredancer Nov 9 '18 at 21:20