1

I'm trying to spend coins from this tx

https://tchain.btc.com/ad7a1ed858eecdd146d9c932779aecae4b33f068d29cf794fad6de20f5a5d449

The scriptpubkey is simple:

1 OP_CHECKSEQUENCEVERIFY OP_DROP OP_SHA256 6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b OP_EQUAL

SHA256 (1) = 6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b

So, I just need to push 1 to the stack using OP_1

Here is my transaction:

bitcoin-cli -testnet decoderawtransaction 020000000149d4a5f520ded6fa94f79cd268f0334baeec9a7732c9d946d1cdee58d81e7aad0000000001510100000001904c96000000000017a914f45d94733d430261962932e0c847075195916a048700000000
{
  "txid": "51060bbaf1b29b2ec3b1bb4eef0d56f61121e4df167768f52e6f67f81321eaf5",
  "hash": "51060bbaf1b29b2ec3b1bb4eef0d56f61121e4df167768f52e6f67f81321eaf5",
  "version": 2,
  "size": 84,
  "vsize": 84,
  "weight": 336,
  "locktime": 0,
  "vin": [
    {
      "txid": "ad7a1ed858eecdd146d9c932779aecae4b33f068d29cf794fad6de20f5a5d449",
      "vout": 0,
      "scriptSig": {
        "asm": "1",
        "hex": "51"
      },
      "sequence": 1
    }
  ],
  "vout": [
    {
      "value": 0.09850000,
      "n": 0,
      "scriptPubKey": {
        "asm": "OP_HASH160 f45d94733d430261962932e0c847075195916a04 OP_EQUAL",
        "hex": "a914f45d94733d430261962932e0c847075195916a0487",
        "reqSigs": 1,
        "type": "scripthash",
        "addresses": [
          "2NFXJy8mvz7ZiT4VVN29xPGC38hTygd3AyJ"
        ]
      }
    }
  ]
}

When I use sendrawtransaction I got

mandatory-script-verify-flag-failed (Script evaluated without error but finished with a false/empty top stack element) (code 16)

Is my redeem script wrong? Or it's something wrong with the scriptpubkey ?

1 Answer 1

2

The SHA256 of 1 is 4bf5122f344554c53bde2ebb8cd2b7e3d1600ad631c385a5d7cce23c7785459a

$ printf "01" | xxd -r -p | openssl sha256
(stdin)= 4bf5122f344554c53bde2ebb8cd2b7e3d1600ad631c385a5d7cce23c7785459a
$ printf "31" | xxd -r -p | openssl sha256
(stdin)= 6b86b273ff34fce19d6b804eff5a3f5747ada4eaa22f1d49c01e52ddb7875b4b

You were probably trying to do the SHA256 of the ascii character "1" which has a byte value of 0x31 or 41 in decimal.

1
  • 1
    oh.. I think this is 99% of all my problems. Thank you
    – Andrew
    Nov 16, 2018 at 3:31

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.