Bitcoin Stack Exchange is a question and answer site for Bitcoin users, developers, and enthusiasts. It only takes a minute to sign up.
Sign up to join this community
I am wondering whether each bitcoin address is unique. I would assume yes. Then, how is this enforced given the distributed address generation?
As I understand it, each time an address is generated, a new key-pair is also generated. On what basis is this done? Since the address is the hash of the public half of the key-pair that would also allow (at least theoretically) multiple public keys to have the same hash.
By the pigeonhole principle yes, there could be two bitcoin addresses that are the same.
The Pigeonhole Principle states, that if there are N items for M spots with N > M then there must be at least 2 of the N items in one of the M spots.
For Bitcoin this means we want/need but might never reach an infinite amount of addresses for an infinite amount of transactions. (but we can reuse addresses; I dont want to get into that) But each addresses is mapped into a space. The space is a certain size (however long addresses are). So by the principle above N = number of transactions/needed addresses = trending to infinity (if bitcoin goes on forever) and M = the size of the address space.
Well, fitting infinity into a finite space means, there would be two of the same addresses. But our finite space is so large that it will take us a long time to fill it up, and the possibility of filling a space of M twice is so small in this case, it's for all intents and purposes zero.
TL;DR: There are so many addresses that it is improbable that anyone will ever generate a duplicate of another address in use – as long as random number generators work as they should.
Bitcoin addresses consist of an alphanumerical string with a length of up to 34 characters, excluding the capital "O", the capital "I" and the lowercase "l", as well as the number "0". This would allow for 58^34 possible combinations, however, as some of the positions are used for a checksum this is reduced to 2^160 valid addresses. The checksum on the other hand allows to detect mistyped addresses as invalid, so that it is highly unlikely to accidentally input another valid address.
Even if we generously assume that at some point there will be one trillion addresses (approx. 160 for each of this planet's population), according to the simple approximation formula for the Birthday attack given on Wikipedia, the chance is 3.42*10^(-27) that any two of those Bitcoin addresses collide. In comparison, the figure of addresses that were ever used to receive bitcoins was just over 13 million in May 2013.
Especially as the protocol at any point could be adapted to accept even longer addresses, we can say, yes, it is theoretically possible, but unlikely enough that we can assume for our purposes that it will never happen.*
To answer your other question: For each address there apparently are 2^96 different private keys whose corresponding public key will map to the same address. So to actually try to pursue Bitcoin theft, it would be much more sensible to just generate random private keys and hope to find one that has a corresponding address with money on it. In all likelihood the power for such calculations would cost more than anyone could earn with such a scheme.
*As long as certain random number generators work as well as they should... :)
It is enforced simply having such an enormous number of addresses, that generating one equal to another one is so unlikely it can be considered as good as impossible.
