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Richard Anthony Hein
Richard Anthony Hein
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It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Update: There It is actually more to this and I will have to dig up the researchalso a sum of squares.

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Update: There is actually more to this and I will have to dig up the research.

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Update: It is also a sum of squares.

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Richard Anthony Hein
Richard Anthony Hein
  • 119
  • 6

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Update: There is actually more to this and I will have to dig up the research.

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Update: There is actually more to this and I will have to dig up the research.

Anon proposed changes arguing the number is 3652501241 base 10 which is incorrect. Added an explanation.
Source Link
Richard Anthony Hein
Richard Anthony Hein
  • 119
  • 6

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

It was chosen because it is a prime number, and also because 4190024921 is the hypotenuse of a primitive Pythagorean triple: 4190024921^2 = 2924728880^2 + 3000378279^2

Edit: Note that you must consider byte order. The TCP protocol requires the number to be encoded in big-endian. 0xf9beb4d9 (little) = 0xd9b4bef9 (big)

See https://stackoverflow.com/a/13514942 for more info about that.

Source Link
Richard Anthony Hein
Richard Anthony Hein
  • 119
  • 6