btc RBF insufficient fee, rejecting replacement

Question

I try to replace this transaction 13bc8f787f7c972702b6d14b8c0b36335aac5d0027800e2de277910a5eff86fb by higher fee, when broadcast return err: broadcast error, -26: insufficient fee, rejecting replacement d05cdb24407169b39abfddd03ae9bef33a1eb49a7f59db4a39c19688a5af99b1, less fees than conflicting txs; 0.00003562 < 0.00009786

I would like to know how to calculate the minimum replacement fee (0.00009786)，

the getmempoolinfo：{"result":{"loaded":true,"size":42800"bytes":80705990,"usage":253822900,"total_fee":6.57420956,"maxmempool":300000000,"mempoolminfee":0.00002600,"minrelaytxfee":0.00001000,"incrementalrelayfee":0.00001000,"unbroadcastcount":0,"fullrbf":false},"error":null,"id":"curltest"}

Answer 1

The replacement transaction must pay for its own bandwidth in addition to the amount paid by the original transactions at or above the rate set by the node's minimum relay fee setting. For example, if the minimum relay fee is 1 satoshi/byte and the replacement transaction is 500 bytes total, then the replacement must pay a fee at least 500 satoshis higher than the sum of the originals.

So to calculate the minimum replacement fee for your tx, calculate the minrelaytxfee from your mempoolinfo times the size of your replacement tx.