0

Further to the following question:

Can the same set of private keys be used multiple times in a multisig wallet?

I tried to create a multisig wallet with keys (A and (B or C)) in Sparrow wallet using the policy suggested by @Vojtěch Strnad. However, it threw an "invalid output descriptor" error. If I try to create a simple 2 of 4 multisig wallet, Sparrow wallet generates the following descriptor:

wsh(sortedmulti(2,Keystore1,Keystore2,Keystore3,Keystore4))

This appears to be a different notation. What should the descriptor be in Sparrow wallet for a multisig wallet supporting keys (A and (B or C)) ? The Sparrow wallet GUI doesn't seem to provide options to create more complex wallets such as this.

Improve this question
2
  • Have you tried putting wsh(...) around the miniscript compiler output? It can only be used inside P2WSH for now.
    – Pieter Wuille
    Commented Aug 15, 2023 at 13:46
  • So overall it'd be wsh(and_v(or_c(pk(B),v:pk(C)),pk(A))), possibly replacing the A/B/C with the kind of key expressions that Sparrow uses (which I'm unfamiliar with).
    – Pieter Wuille
    Commented Aug 15, 2023 at 13:54

1 Answer 1

Reset to default
1

Such a policy would have to be described using a Miniscript Output Descriptor, which i believe the Sparrow wallet does not support yet (as of August 2023).

A simpler k-of-N multisig policy can however be described using a non-Miniscript Output Descriptor (multi or sortedmulti), which are supported by the Sparrow wallet.

If you want to use the Miniscript Descriptor, you could import it on a Bitcoin Core wallet (starting with version 25.0 for full support) until Sparrow supports Miniscript.

Improve this answer
2
  • Could the same thing be achieved using a simple 3 of 4 wallet with keys AABC? This would result in key A always being required for a withdrawal and at least one of B and C?
    – Guru Josh
    Commented Aug 15, 2023 at 21:59
  • Yes, but you'd have to derive another key from the same xpub (or duplicate the key, but that's worse).
    – Antoine Poinsot
    Commented Aug 16, 2023 at 6:48

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.